4b^2+10b+7=4+2b

Solution for 4b^2+10b+7=4+2b equation:

4b^2+10b+7=4+2b

We move all terms to the left:

4b^2+10b+7-(4+2b)=0

We add all the numbers together, and all the variables

4b^2+10b-(2b+4)+7=0

We get rid of parentheses

4b^2+10b-2b-4+7=0

We add all the numbers together, and all the variables

4b^2+8b+3=0

a = 4; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·4·3
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*4}=\frac{-12}{8}
=-1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*4}=\frac{-4}{8}
=-1/2
$